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Question

The possible value of Θϵ(0,π)suchthatsin(Θ)+sin(4Θ)+sin(7Θ)=0are:

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Solution

sinθ+sin4θ+sin7θ=0
(sinθ+sin7θ)+sin4θ=0
2sin(θ+7θ2)cos(θ7θ2)+sin4θ=0
2sin4θcos3θ+sin4θ=0
sin4θ(2cos3θ+1)=0
sin4θ=0 or cos3θ=12
4θ=nπ or 3θ=2nπ±2π3
θ=nπ4 or θ=2nπ3+2π9
As θ(0,π)
θ=π4 or 2π4 or 3π4
θ=2π9,2π32π9,2π3+2π9
Total number of solutions=3+3=6.

1195587_1195265_ans_000625aaa8564cbbaf70ed4695edf51a.jpg

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