The possible value of $(x |$ if ${(x |}^{2} - 6 (x | + 8 = 0$ is equal to

$8$

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$1$

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$2$

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$5$

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Solution

The correct option is C
$2$

This can be considered as a quadratic in $(x |$ , $| x |^{2} - 6 | x | + 8 = 0$

$\Rightarrow (| x | - 4) (| x | - 2) = 0$

$\Rightarrow | x | = 4$ or $| x | = 2$

Hence the correct answer is Option B.

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Similar questions

Which of the following is the possible value of $(x |$ if ${(x |}^{2} - 6 (x | + 8 = 0$

x

x^{2} - 6 x + 5 \leq 0

x^{2} - 2 x > 0

x

$x^{2} - 6 x + 5 \leq 0, x^{2} - 2 x > 0$ where $x$ is an integer. Find all the possible values of $x$ .

| x^{2} + 6 x + p | = x^{2} + 6 x + p

\forall x \in R

p

x^{2} + 6 x + 8

{x \in R ∣ ∣ x^{2} - 2 x - 8 \leq 0}

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