The possible value(s) of a for which the equation x2+2x−(a3−3a−3)=0 has real roots is/are
A
4
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B
−1
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C
6
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D
2
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Solution
The correct options are A4 B−1 C6 D2 x2+2x−(a3−3a−3)=0 For real roots, D≥0 ⇒4+4(a3−3a−3)≥0⇒1+a3−3a−3≥0⇒a3−3a−2≥0⇒(a+1)(a2−a−2)≥0⇒(a+1)2(a−2)≥0 ∴a∈{−1}∪[2,∞)