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Question

The possible values of 1x2+3 lie in the interval


A

[16,0)

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B

(0,16)

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C

(0,13]

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D

[13,0)

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Solution

The correct option is C

(0,13]


We know that x20xR

x2+33;xR

3x2+3<

131x2+3>1

0<1x2+313

So, the possible values of 1x2+3 lie in the interval (0,13]


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