The postulate used in the division of line segment to draw A 3 C parallel to A 5 B is -A- Corresponding angles are equalB- Alternate interior angles are equalC- Co-interior angles are supplementaryD- Perpendicular bisector theorem

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Standard X

Mathematics

Construction of a Similar Triangle, When One Vertex Is Common

The postulate...

Question

The postulate used in the division of line segment to draw $A_{3} C$ parallel to $A_{5} B$ is :

Corresponding angles are equal

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Alternate interior angles are equal

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Co-interior angles are supplementary

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Perpendicular bisector theorem

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Solution

The correct option is A Corresponding angles are equal

Here we use the principle that when corresponding angles are equal, the lines are parallel.
$∠ A A_{3} C = ∠ A A_{5} C$ as $A_{3} C$ is parallel to $A_{5} B$

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Similar questions

Q. Construction of a

Δ A^{'} C^{'} B

similar to

Δ A C B

is shown in the figure below, which condition is used to construct

A^{'} C^{'}

A C

Q. In the given image, segment

A B

has been divided in the ratio

3 : 2

. This is done by
1) Drawing

∠ B A X

2) marking equal lengths

A A_{1}, A_{1} A_{2}, A_{2} A_{3}, A_{3} A_{4} & A_{4} A_{5}

3) Point

A_{5}

is joint to point B
4)

A_{3} C

is drawn parallel to

A_{5} B

by using which of the properties of parallel lines?

Q. A triangle ABC with AB = 6 cm,

∠ A = 30^{\circ}

and

∠ B = 60^{\circ}

is given. The image of construction of

Δ A B^{'} C^{'}

similar to

Δ A B C

with base

A B^{'} = 8 c m

is given below.

The postulate used for drawing B'C' || BC is:

Q. A triangle ABC with sides BC =7cm,

∠ B = 45^{\circ}, ∠ A = 105^{\circ}

is given. The image of constructing a similar triangle of

Δ A B C

whose sides are

\frac{3}{4}

times the corresponding sides of the

Δ A B C

is given below.

The condition used to draw A'C' parallel to AC:

The postulate used in the division of line segment to draw

A_{3} C

parallel to

A_{5} B

is :

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The postulate used in the division of line segment to draw A3C parallel to A5B is :

The correct option is A Corresponding angles are equal Here we use the principle that when corresponding angles are equal, the lines are parallel. ∠AA3C=∠AA5C as A3C is parallel to A5B

The postulate used in the division of line segment to draw $A_{3} C$ parallel to $A_{5} B$ is :

The correct option is A Corresponding angles are equal

Here we use the principle that when corresponding angles are equal, the lines are parallel.
$∠ A A_{3} C = ∠ A A_{5} C$ as $A_{3} C$ is parallel to $A_{5} B$