Question

The potential at a point due to a charge of $5\times {10}^{-7}C$ located $10cm$ away is:

• A. $3.5\times {10}^{5}V$
• B. $3.5\times {10}^{4}V$
• C. $4.5\times {10}^{4}V$
• D. $4.5\times {10}^{5}V$

Answer 1

Answer: (C)

$4.5\times {10}^{4}V$

Here $q=5\times {10}^{-7}C,r=10cm=0.1m$
Potential, $V=\frac{1}{4\pi {\epsilon }_0}\frac{q}{r}=\frac{9\times {10}^9\times 5\times {10}^{-7}}{0.1}=4.5\times {10}^{4}V$