The potential at a point is $20 V$ . What will be the work done to bring a charge of $0.5 C$ from infinity to this point?

$5 J$

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$10 J$

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$20 J$

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$15 J$

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Solution

The correct option is B
$10 J$

$G i v e n,$

$Charge q = 0.5 C$

$Potential difference V = 20 Volts$

$We know that Work done W = qV$

$Therefore, W = 0.5 C \times 20 V = 10J$

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The potential at a point is 20 V. What will be the work done to bring a charge of 0.5 C from infinity to this point?

The correct option is B 10 J Given, Charge q = 0.5 C Potential difference V = 20 Volts We know that Work done W = qV Therefore, W = 0.5 C × 20 V = 10J

The potential at a point is $20 V$ . What will be the work done to bring a charge of $0.5 C$ from infinity to this point?

The correct option is B
$10 J$

$G i v e n,$

$Charge q = 0.5 C$

$Potential difference V = 20 Volts$

$We know that Work done W = qV$

$Therefore, W = 0.5 C \times 20 V = 10J$