The potential at a point x (in m) due to some charge configuration on the x-axis is given by $V (x) = (20 x^{2} - 4) V$ . Find the electric field as a function of x.

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Solution

We know that, $E_{x} = \frac{- d V}{d x} = - \frac{d (20 x^{2} - 4)}{d x} = - 40 x V / m$

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The potential at a point x (in m) due to some charge configuration on the x-axis is given by V(x)=(20x2−4) V. Find the electric field as a function of x.

We know that, Ex=−dVdx=−d(20x2−4)dx=−40x V/m

The potential at a point x (in m) due to some charge configuration on the x-axis is given by $V (x) = (20 x^{2} - 4) V$ . Find the electric field as a function of x.

We know that, $E_{x} = \frac{- d V}{d x} = - \frac{d (20 x^{2} - 4)}{d x} = - 40 x V / m$