Question

The potential barrier between the $p-n$ junction is $0.8\text{V}$. If the width of the depletion region is $8\times {10}^{-7}\text{m}$ then the intensity of electric field in this region is ____$\times {10}^6\text{V/m}$.

Answer 1

Given that,
Potential barrier $\left(V\right)=0.80\text{V}$

Width of deflection region $\left(W\right)=0.8\times {10}^{-7}\text{m}$

The electric field $\left(E\right)$ is given by

$E=\frac{V}{W}$

$\Rightarrow E=\frac{0.80\text{V}}{8\times {10}^{-7}\text{m}}$

$\Rightarrow E=1\times {10}^6{\text{Vm}}^{-1}$

Hence, the correct answer is $1.$