Question

The potential difference across the $100\Omega$ resistance in the circuit is measured by a voltmeter of $900\Omega$ resistance. The percentage error made in reading the potential difference is

• A. $\frac{10}{9}$
• B. $0.1$
• C. $1.0$
• D. $10.0$

Answer 1

The correct option is A $\frac{10}{9}$

The potential difference across the $=100\Omega$ resistance in the circuit voltmeter $=900\Omega$

percentage error $=\frac{100}{900}\times 100=\frac{10}{9}$%