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Electric Potential and Potential Difference

The potential...

Question

The potential difference across the Coolidge tube is $20 k V$ and $10 m A$ current flows through the voltage supply. Only $0.5 %$ of the energy carried by the electrons striking the target is converted into X-rays. The power carried by the X-ray beam is $P$ . Then

A

P = 0.1 W

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B

P = 1 W

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C

P = 2 W

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D

P = 10 W

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Solution

The correct option is B $P = 1 W$
The energy carried out by the electrons is the product of voltage and current
$P o w e r = V \times I = 20 k V \times 10 m A = 200 W$
Now, only $0.5 %$ is carried out by X-rays which is $\frac{0.5 \times d 200 W}{100} = 1 W$

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