The potential difference applied to an X-ray tube in 5kV and the current through it is 3.2mA. Then the number of electrons striking the target per second is

2 \times 10^{16}

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5 \times 10^{18}

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1 \times 10^{17}

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4 \times 10^{5}

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Solution

The correct option is A $2 \times 10^{16}$
$n = \frac{I^{+}}{e} = \frac{3.2 \times 10^{- 3} \times 1}{1.6 \times 10^{- 19}} = 2 \times 10^{16}$

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The potential difference applied to an X-ray tube in 5kV and the current through it is 3.2mA. Then the number of electrons striking the target per second is

The correct option is A 2×1016n=I+e=3.2×10−3×11.6×10−19=2×1016

The correct option is A $2 \times 10^{16}$
$n = \frac{I^{+}}{e} = \frac{3.2 \times 10^{- 3} \times 1}{1.6 \times 10^{- 19}} = 2 \times 10^{16}$