The potential difference applied to an x-ray tube is 5 KV and the current through it is 32 mA. The number of electrons striking the target per second is (e=1.6×10−19C)
A
1.6×106s−1
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B
2×10−6s−1
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C
4×1016s−1
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D
2×1016s−1
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Solution
The correct option is D2×1016s−1 Current I=netnt=ie=3.2×10−31.6×10−19=2×1016s−1