The potential difference between point A and B is

\frac{20}{7}

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\frac{40}{7}

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\frac{10}{7}

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0

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Solution

The correct option is D $0$
$\begin{matrix} I_{1} = \frac{V}{R} = \frac{10}{14} = \frac{5}{7} A I_{2} = \frac{10}{7} A V_{P Q} = V_{P} - V_{B} = I_{1} \times 8 = \frac{5}{7} \times 8 V_{P} - V_{B} = \frac{40}{7} v o l t . . . . . (1) V_{P A} = I_{2} \times 4 = \frac{10}{7} \times 4 = \frac{40}{7} v o l t V_{P} - V_{A} = \frac{40}{7} v o l t . . . . . . . (2) B y (1) a n d (2) V_{A} - V_{B} = 0 \end{matrix}$

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(0, 0, - 7)

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The potential difference between point A and B is

The correct option is D 0I1=VR=1014=57AI2=107AVPQ=VP−VB=I1×8=57×8VP−VB=407volt.....(1)VPA=I2×4=107×4=407voltVP−VA=407volt.......(2)By(1)and(2)VA−VB=0