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Byju's Answer
Standard XII
Physics
Partially Filled Dielectrics
The potential...
Question
The potential difference between points A and B is
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Solution
Equivalent resistance in both the branches is,
R
Eq
1
=
8
+
6
=
14
Ω
R
Eq
2
=
4
+
3
=
7
Ω
Now equivalent resitance of circuit is,
R
eq
=
14
×
7
14
+
7
=
14
3
Ω
Net current
=
I
=
V
R
eq
=
10
14
3
=
15
7
A
From current Division,
I
1
=
7
21
×
15
7
=
5
7
A
I
2
=
I
−
I
1
I
2
=
15
7
−
5
7
=
10
7
A
From KVL
8
I
1
+
V
B
−
V
A
−
4
I
2
=
0
⇒
V
A
−
V
B
=
8
×
5
7
−
4
×
10
7
⇒
V
A
−
V
B
=
0
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