The potential difference between two parallel plates is 104 volt. If the plates are separated by 0.5cm, the force on an electron between the plates is :
A
2×104N
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B
3.2×10−13N
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C
20N
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D
32×1012N
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Solution
The correct option is B3.2×10−13N We know E=VL E=1040.5×10−2
E=2×106 |force on an electron| =|qE| =2×106×1.6×10−19 =3.2×10−13N