1
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Question

# The potential difference between two points A and B is 10V. Point A is at higher potential. If a negative charge, q = 2 C, is moved from point A to point B, then the potential energy of this charge will:

A
decrease by 20 J
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B
decrease by 5 J
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C
increase by 5 J
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D
increase by 20 J
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E
increase by 100 J
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Solution

## The correct option is E increase by 20 JThe change in potential energy, ΔU=qΔVAs the charge q=−2C is moved from A to B so potential will decrease 10 V i.e ΔV=−10VThus, ΔU=(−2)(−10)=+20J

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