The potential difference between two points A and B is
A
Zero
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B
Q4πϵ0a(1−1√5)
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C
Q2πϵ0a[1−1√5]
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D
Q4πϵ0a[2−1√5]
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Solution
The correct option is CQ2πϵ0a[1−1√5] Distance from A to −Q and B to +Q=√a2+4a2=√5a Potential difference ΔV=VA−VB =[kQa−kQ√5a]−[kQ√5a−kQa] =2kQa[1−1√5] ΔV=Q2πϵ0a(1−1√5)