The potential difference between two points is 35V and the resistance of the wire connecting the two points is $35 Ω$ . The current in the circuit is ___ A.

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Solution

Given,

Voltage = 35V

Resistance = $35 Ω$

Applying Ohm’s law, $V = I \times R$
$35 = I \times 35$
Hence, I = 1 Ampere

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The potential difference between two points is 35V and the resistance of the wire connecting the two points is 35Ω. The current in the circuit is ___ A.

Given, Voltage = 35V Resistance = 35Ω Applying Ohm’s law, V=I×R 35=I×35 Hence, I = 1 Ampere

The potential difference between two points is 35V and the resistance of the wire connecting the two points is $35 Ω$ . The current in the circuit is ___ A.

Given,

Voltage = 35V

Resistance = $35 Ω$

Applying Ohm’s law, $V = I \times R$
$35 = I \times 35$
Hence, I = 1 Ampere