wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The potential difference of a circuit is doubled. By what factor does the power change in the circuit?

Open in App
Solution

P=(V^2)/R
(We didnt take P=VI because when the voltage is increased current also increases where the resistance is the constant. Aslong as the R is constant the solution is easy to calculate)
P is proportional to the square of voltage. Therefore if the voltage doubles power will square of the voltage ie 4 times.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon