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Electric Generator

The potential...

Question

The potential difference V and current I flowing through an instrument in an AC circuit are given by $V = 5 c o s ω t$ volt and $i = 2 s i n ω t$ ampere respectively. Then the power dissipated in the instrument is

A

0 W

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B

2.5 W

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C

5 W

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D

10 W.

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Solution

The correct option is A 0 W
It is clear from the given information that phase difference between voltage and current is $90^{\circ}$ .
As, $P = V I c o s ϕ$
we will get P=0 because $c o s ϕ = 0$ as $ϕ = 90^{0}$ .

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