The potential energies of first, second and third Bohr's orbit of He $^{+}$ cation are $E_{1}$ , $E_{2}$ and $E_{3}$ respectively. Write the correct sequence of these energies in increasing order.

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Solution

$H e^{+}$ cation is $H -$ like species.

For $H -$ like species, potential energy $E$ is given as $- \frac{13.6 z^{2}}{n^{2}} e V$

whose $z =$ atomic number of $H -$ like species

$n =$ energy level or shell number

Since, there is negative in potential energy expression so, higher the $n$ value smaller is the negative value or higher is the potential energy.

$E = \frac{13.6 z^{2}}{n^{2}} e V$

$E = - k \frac{1}{n^{2}} e V$

$E \propto - \frac{1}{n^{2}}$

where, $k = 13.6 z^{2}$

Here, $z = 2$ for $H e^{+}$

The correct sequence of the potential energies in measuring order is $E_{1} < E_{2} < E_{3}$ .

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The potential energies of first, second and third Bohr's orbit of He+ cation are E1, E2 and E3 respectively. Write the correct sequence of these energies in increasing order.

The potential energies of first, second and third Bohr's orbit of He $^{+}$ cation are $E_{1}$ , $E_{2}$ and $E_{3}$ respectively. Write the correct sequence of these energies in increasing order.