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Question

The potential energy for a force field F is given by U(x, y) = sin(x + y). Magnitude of the force acting on the particle of mass m at (0,π4) is

A
1
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B
2
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C
12
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D
0
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Solution

The correct option is A 1
F=(x,y)=U(x,y)U(x,y)=Uxˆx+Uyˆy=cos(x+y)(ˆx+ˆy)F(x,y)=|U(x,y)|F(0,π4)=|U(x,y)|=cos(π4)|ˆx+ˆy|F(0,π4)=1212+11=1unit
Hence,
option (A) is correct answer.

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