The potential energy function for diatomic molecule is Ux - a-x12 - b-x6- In a stable equilibrium- the distance between the particles is -

The correct option is A (2a/b)^1/6 F = dU/dx = 12a/x^13 6b/x^7 F = 0 x = (2a/b)^1/6 d^2U/dx^2 ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Electrode Potential

The potential...

Question

The potential energy function for diatomic molecule is $U (x) = \frac{a}{x^{12}} - \frac{b}{x^{6}}$ . In a stable equilibrium, the distance between the particles is :

{(\frac{2 a}{b})}^{1 / 6}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{(\frac{a}{b})}^{1 / 6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{(\frac{b}{2 a})}^{1 / 6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{(\frac{b}{a})}^{1 / 6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A ${(\frac{2 a}{b})}^{1 / 6}$
$F = - \frac{d U}{d x} = \frac{12 a}{x^{13}} - \frac{6 b}{x^{7}}$
$At equilibrium, F = 0 or x = {(\frac{2 a}{b})}^{1 / 6}$
$At this value of x, we can see that \frac{d^{2} U}{d x^{2}} is positive.$
$So, potential energy is minimum or equilibrium is stable.$

Suggest Corrections

Similar questions

The potential energy between two atoms in a molecule is gives by, U (x) = $\frac{a}{x^{12}}$ - $\frac{b}{x^{6}}$ , where a and b are postive constant and x is the distant between the atome. The system is in stable equilibrium when

Q. The potential energy between two atoms in a molecule is given by

U (x) = \frac{a}{x^{12}} - \frac{b}{x^{6}}

, where

a

and

b

are

+

ve constants and

x

is the distance between the atoms. The atom is in stable equilibrium when

Q. The potential energy function for the force between two atoms in a diatomic molecule is approximately given by

U (x) = \frac{a}{x^{12}} - \frac{b}{x^{6}}

, where

a

and

b

are constants and

x

is the distance between the atoms. lf the dissociation energy of the molecule is

D = [U (x = \infty) - U_{a t e q u i l i b r i u m}],

then

D

is equal to

Q. The potential energy function for the force between two atoms in a diatomic molecule which is approximately given as,

U (x) = \frac{a}{x^{12}} - \frac{b}{x^{6}}

. Where

a & b

are constants and

x

is the distance between the atoms. The disassociation energy of the molecule,

D = [U (x = \infty) - U_{e q u i l i b r i u m}]

Q. The potential energy function for the force between two atoms in a diatomic molecule is approximately given by

U (x) = \frac{a}{x^{12}} - \frac{b}{x^{6}}

, where

a

and

b

are constants and

x

is the distance between the atoms. If the dissociation energy of the molecule is

D = [U_{x = \infty} - U_{at equilibrium}]

D

Join BYJU'S Learning Program

The potential energy function for diatomic molecule is U(x)=ax12−bx6. In a stable equilibrium, the distance between the particles is :

The correct option is A (2ab)1/6F=−dUdx=12ax13−6bx7At equilibrium, F=0 or x=(2ab)1/6At this value of x, we can see that d2Udx2 is positive.So, potential energy is minimum or equilibrium is stable.

The potential energy function for diatomic molecule is $U (x) = \frac{a}{x^{12}} - \frac{b}{x^{6}}$ . In a stable equilibrium, the distance between the particles is :