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Question

The potential energy (in SI units) of a particle of mass 2 kg in a conservative field is U=6x8y. If the initial velocity of the particle is u=1.5^i+2^j m/s, then the total distance travelled by the particle in first two seconds is

A
10 m
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B
12 m
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C
15 m
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D
18 m
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Solution

The correct option is C 15 m
F=Ux^iUy^j=[6^i]+[8]^j=6^i+8^j
a=3^i+4^j m/s2 has same direction as that of u=3^i+4^j2 m/s
So, a=5 m/s2,u=52 m/s
Since u and a are in same direction, particle will move along a straight line.
S=ut+12at2
Given t=2 s
S=52×2+12×5×22=5+10=15 m

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