The potential energy of a body at height h is mgh. Then its kinetic energy just before hitting the ground is

mv²

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√2gh

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mgh

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√2mgh

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Solution

The correct option is C
mgh

From the law of conservation of mechanical energy, the potential energy of a body at height h is converted into kinetic energy when it falls down. So, the magnitude of kinetic energy just before hitting the ground is equal to the potential energy at height h which is mgh.

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Similar questions

A ball of mass m is thrown vertically up with an initial velocity so as to reach a height h.The correct statement is :

(a) Potential energy of the ball at the ground is mgh.

(b) Kinetic energy of the ball at the ground is zero.

m v^{2}

5 k g

(

g = 10 m / s^{2})

10 k g

10 m

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