The potential energy of a certain spring, when stretched through a distance $^{'} S^{'}$ , is $10$ Joule. Find the amount of work (in joule) that must be done on this spring to stretch it through an additional distance $^{'} S^{'}$ .

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Solution

$v_{1} = \frac{1}{2} k 5^{2}$
$v_{2} = \frac{1}{2} k 25^{2}$
$△ v$
$= \frac{1}{2} k 45^{2} - = \frac{1}{2} k 35^{2}$
$= 3 (\frac{1}{2} \times k 5^{2})$
$3 (v_{1}) = 3 (10) = 30 J$

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The potential energy of a certain spring, when stretched through a distance ′S′, is 10 Joule. Find the amount of work (in joule) that must be done on this spring to stretch it through an additional distance ′S′.

v1=12k52 v2=12k252 △v=12k452−=12k352=3(12×k52) 3(v1)=3(10)=30J

The potential energy of a certain spring, when stretched through a distance $^{'} S^{'}$ , is $10$ Joule. Find the amount of work (in joule) that must be done on this spring to stretch it through an additional distance $^{'} S^{'}$ .

$v_{1} = \frac{1}{2} k 5^{2}$
$v_{2} = \frac{1}{2} k 25^{2}$
$△ v$
$= \frac{1}{2} k 45^{2} - = \frac{1}{2} k 35^{2}$
$= 3 (\frac{1}{2} \times k 5^{2})$
$3 (v_{1}) = 3 (10) = 30 J$