Question

The potential energy of a particle executing S.H.M. is 2.5 J, when its displacement is half of amplitude. The total energy of the particle be

• A. 18J
• B. 10J
• C. 12J
• D. 2.5J

Answer 1

The correct option is B

10J

$\frac{Potentialenergy\left(U\right)}{Totalenergy\left(E\right)}=\frac{\frac{1}{2}m{\omega }^2{y}^2}{\frac{1}{2}m{\omega }^2{a}^2}=\frac{y^2}{a^2}$

So, $\frac{2.5}{E}=\frac{{\left(\frac{a}{2}\right)}^2}{a^2}\Rightarrow E=10J$