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Question

The potential energy of a particle executing SHM varies sinusoidally with frequency f. The frequency of oscillation of the particle will be:

A
f2
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B
f2
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C
f
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D
2f
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Solution

The correct option is A f2
Let the displacement equation of the particle executing SHM is x=Asin(wt+ϕ)
where w=2πf
Thus potential energy of the particle is given by P.E=12kx2
P.E=12kA2sin2(wt+ϕ)
P.E=12kA2[1cos2wt2]
P.E=14kA214kA2cos2wt
Thus the particle oscillates at a frequency half than that of varying potential energy.
Given that P.E oscilates at frequency f frequency of oscillation of the particle f=f2



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