The potential energy of a particle of mass 0.1kg, moving along x-axis, is given by U=5x(x−4)J where x is in metres. It can be concluded that
A
the particle is acted upon by a constant force
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B
the speed of the particle is maximum at x = 2 m
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C
the particle executes simple harmonic motion
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D
the period of oscillation of the particle is π/5 s.
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Solution
The correct options are B the speed of the particle is maximum at x = 2 m C the particle executes simple harmonic motion D the period of oscillation of the particle is π/5 s.