The potential energy of a simple harmonic oscillator of mass 2 kg in its mean position is 5J. If its total energy is 9J and its amplitude is 0.01 m,its time period would be
kinetic energy at
mean position= total energy-potential energy at mean
position=9J−5J=4J
kinetic energy at mean position=12mvmax2
⇒12mvmax2=4J
⇒vmax=√4×22m/s=2m/s
⇒Aω=A2πT⇒A2πT=2m/s⇒T=Aπ=0.01π=π100s