Question

The potential energy of an electron present in the ground state of $L{i}^{2+}$ ion is:

• A. $+\frac{3e^2}{4\pi {\epsilon }_{0}r}$
• B. $-\frac{3e}{4\pi {\epsilon }_{0}r}$
• C. $-\frac{3e^2}{4\pi {\epsilon }_{0}r}$
• D. $+\frac{3e^2}{4\pi {\epsilon }_0{r}^2}$

Answer 1

The correct option is C $-\frac{3e^2}{4\pi {\epsilon }_{0}r}$

$PotentialEnergy=\frac{-Z{k}_e{e}^2}{r}$
for $L{i}^{2+}Z=3$
$P.E=\frac{-3e^2}{4\pi {\epsilon }_{0}r}$