The potential energy of particle of mass -m- is given by U-1-2kx2 for x-0 and U - 0 for x - 0- If total mechanical energy of the particle is E- Then its speed at x-2E-k is

Potential energy of particle at x=√(2E/k) is zero ∴ K.E = E ⇒1/2mv^2=E or v=√(2E/m) ...

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Law of Conservation of Mechanical Energy

The potential...

Question

The potential energy of particle of mass 'm' is given by $U = \frac{1}{2} k x^{2}$ for x<0 and U = 0 for x $\geq$ 0. If total mechanical energy of the particle is E. Then its speed at $x = \sqrt{\frac{2 E}{k}}$ is

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\sqrt{\frac{2 E}{m}}

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\sqrt{\frac{E}{m}}

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\sqrt{\frac{E}{2 m}}

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U = \frac{1}{2} k x^{2}

x \geq 0.

x = \sqrt{\frac{2 E}{k}}

U = \frac{1}{2} k x^{2}

\geq

x = \sqrt{\frac{2 E}{k}}

U = \frac{1}{2} k x^{2}

x < 0

U = 0

x \geq 0

x = - \sqrt{\frac{2 E}{k}}

k x^{2}

x \geq 0

- \sqrt{2 E / K}

U = \frac{1}{2} K X^{2} f o r X < 0 a n d U = 0 f o r X > 0

X = - \sqrt{\frac{2 E}{K}}

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