1
Question
The potential energy of the dipole in the equilibrium position is :
The potential energy of the dipole in the equilibrium position is :
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Solution
The correct option is B −3×10−23J
As dipole is in equilibrium P.E. should be minimum∴θ= angle between dipole and electric field =0o
Now, potential energy
U=−P.E
=−7.68×10−29×4×105
=−3×10−23 J
As dipole is in equilibrium P.E. should be minimum
∴θ= angle between dipole and electric field =0o
Now, potential energy
U=−P.E
=−7.68×10−29×4×105
=−3×10−23 J
Now, potential energy
U=−P.E
=−7.68×10−29×4×105
=−3×10−23 J
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