Question

The potential energy per unit volume of a stretched wire is

• A. $\frac{1}{2}\times load\times extersion$
• B. $\frac{1}{2}\times stress\times strain$
• C. $stress\times strain$
• D. $load\times extension$

Answer 1

Answer: (B)

$\frac{1}{2}\times stress\times strain$

$\text{Potential Energy per unit volume}=\frac{1}{2}\times \text{stress}\times \text{strain}$