wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The potential field of an electric field E=(y^i+x^j) is

A
V=xy+constant
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
V=(x+y)+constant
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
V=(x2+y2)+constant
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
V=constant
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A V=xy+constant
dV=E.dr
=(y^i+x^j).(dx^i+dy^j+dz^k)
=(ydx+xdy)=d(xy)
Integrating, we get
V=xy+constant

flag
Suggest Corrections
thumbs-up
23
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electric Field Due to Charge Distributions - Approach
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon