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Byju's Answer
Standard XIII
Physics
Potential Gradient and Relation between Electric Field and Potential
The potential...
Question
The potential field of an electric field
→
E
=
(
y
^
i
+
x
^
j
)
is
A
V
=
−
x
y
+
constant
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B
V
=
x
y
+
constant
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C
V
=
−
(
x
2
+
y
2
)
+
constant
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D
V
=
constant
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Solution
The correct option is
A
V
=
−
x
y
+
constant
d
V
=
−
→
E
.
d
→
r
=
−
(
y
^
i
+
x
^
j
)
.
(
d
x
^
i
+
d
y
^
j
+
d
z
^
k
)
=
−
(
y
d
x
+
x
d
y
)
=
−
d
(
x
y
)
Integrating, we get
V
=
−
x
y
+
constant
Suggest Corrections
2
Similar questions
Q.
The potential field of an electric field
→
E
=
(
y
^
i
+
x
^
j
)
is
Q.
An electric field is given by
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(
y
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i
+
x
^
j
)
N/C
. The work done in moving a
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−
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=
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^
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→
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)
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is
Q.
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of an electrostatic field
→
E
=
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(
y
^
i
+
x
^
j
)
,
where a is a constant.
Q.
The divergence of the vector field
(
x
−
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^
i
+
(
y
−
x
)
^
j
+
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)
^
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Q.
Figure show some of the electric field lines corresponding to an electric field. The figure suggest that (E= electric field, V=potential).
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