The potential gradient along the length of a uniform wire is $10$ volt/m B and C are two points at $30$ cm and $60$ cm in a scale fitted along the wire. The pd between B and C is

3 V

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0.4 V

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7 V

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4 V

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Solution

The correct option is A $3 V$
$l_{B C} = 60 - 30 = 30 c m$
$V = (\frac{Δ V}{l}) l_{B C}$
$= 10 \times \frac{30}{100}$
$V = 3 V$

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The potential gradient along the length of a uniform wire is 10 volt/m B and C are two points at 30 cm and 60 cm in a scale fitted along the wire. The pd between B and C is

The correct option is A 3VlBC=60−30=30cmV=(ΔVl) lBC =10×30100V=3V

The potential gradient along the length of a uniform wire is $10$ volt/m B and C are two points at $30$ cm and $60$ cm in a scale fitted along the wire. The pd between B and C is

The correct option is A $3 V$
$l_{B C} = 60 - 30 = 30 c m$
$V = (\frac{Δ V}{l}) l_{B C}$
$= 10 \times \frac{30}{100}$
$V = 3 V$