The potential of a large liquid drop when eight liquid drops are combined is 20 V. Then, the potential of each single drop was :
The correct option is (A) 10 V
According to the question 8 drops are joined to form a big drop
So,
Volume of 8 drops = Volume of big drop
∴(43πr3)×8=43πR3
After solving
⇒2r=R....(i)
If each small drop has charge q then according to charge conservation
8q=Q....(ii)
We know,
V∝1r
So we can write
or V1V2=r2n
Or,
⇒20V2=2rr
Therefore
⇒V2=10 V
Potential of the small drop is 10 V