The potential of the following cell at 25-C is- Pt H2 1 atm - HNO3 0-1M -NaOH 10-3M- H2 1 atm-Pt

The correct option is C 0.59 V It is a concentration cell, therefore, #160; E^⊖_cell = 0 . #160; pH of HNO_3 = log 10^ 1 = ...

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Byju's Answer

Standard XII

Chemistry

EMF

The potential...

Question

The potential of the following cell at $25^{\circ} C$ is:
$P t ∣ ∣ ∣ \begin{matrix} H_{2} (1 a t m) \end{matrix} ∣ ∣ ∣ \begin{matrix} H N O_{3} 0.1 M \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} N a O H (10^{- 3} M) \end{matrix} ∣ ∣ ∣ \begin{matrix} H_{2} (1 a t m) \end{matrix} ∣ ∣ ∣ P t$

- 0.059 V

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0.059 V

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0.59 V

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0.5 V

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Solution

The correct option is C - $0.59 V$
It is a concentration cell, therefore, $E_{c e l l}^{⊖} = 0$ .

$p H$ of $H N O_{3} = - l o g 10^{- 1} = 1$
$p O H$ of $N a O H$ = $- l o g 10^{- 3} = 3$

$∴$ $p H$ of $N a O H$

$= 14 - 3$

$= 11$

$∴ E = - 0.059 (p H_{c} - p H_{a})$

$= - 0.059 (11 - 1)$

$= - 0.59 V$

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