Question

The potentials of the two plates of capacitor are + 10V and -10 V. The charge on one of the plates is 40 C. The capacitance of the capacitor is
[AFMC 2005]

• A. 2 F
• B. 4 F
• C. 0.5 F
• D. 0.25 F

Answer 1

The correct option is A 2 F

Potential difference between the plates
= 10 - (-10)
= 20 V

Q = 40 C
Q = CV
$\Rightarrow C=\frac{Q}{V}=\frac{40}{20}=2F$
C = 2F