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f-R Relationship

The power in ...

Question

The power (in diopters) of an equiconvex lens with radii of curvature of $10 c m$ and refractive index of $1.6$ is:

A

- 12

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B

+ 12

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C

+ 1.2

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D

- 1 / 2

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Solution

The correct option is B $+ 12$
Power= $p = \frac{1}{f} = (n - 1) (\frac{1}{R} - \frac{1}{- R}) = 0.6 (2 / R) = 1.2 / R = 1.2 / .1 = + 12$ Diopters.

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