Question

The power input to a 3-phase induction motor is 45 kW. The total stator losses are 1.5 kW when the motor is running at 4% slip, the internal mechanical power developed is

• A. 41.76 kW
• B. 43.5 kW
• C. 42.56 kW
• D. 40.5 kW

Answer 1

The correct option is A 41.76 kW

Rotor input (or) air gap power
= 45 - 1.5 = 43.5 kW
s = 0.04
Internal mechanical power developed is
= 43.5 (1 - 0.04)
= 43.5 $\times$ 0.96 = 41.76 kW