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Question

The power input to a 3-phase induction motor is 45 kW. The total stator losses are 1.5 kW when the motor is running at 4% slip, the internal mechanical power developed is

A
41.76 kW
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B
43.5 kW
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C
42.56 kW
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D
40.5 kW
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Solution

The correct option is A 41.76 kW
Rotor input (or) air gap power
= 45 - 1.5 = 43.5 kW
s = 0.04
Internal mechanical power developed is
= 43.5 (1 - 0.04)
= 43.5 × 0.96 = 41.76 kW

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