The power obtained in a reactor using U 235 disintegration is 1000 kW- What is the mass decay of U 235 per hour-

As, E = mc2 1000 * 103 * 3600 = m (3 * 108)2 (we took 1000 × 103 since KW) Therefore, by solving the above calculation we get, m = 40 microgram ...

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Standard X

Physics

Nuclear Fission

The power obt...

Question

The power obtained in a reactor using U²³⁵ disintegration is 1000 kW . What is the mass decay of U²³⁵ per hour ?

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Solution

As, E = mc²

1000 * 10³ * 3600 = m (3 * 10⁸)²
(we took 1000 × 10³since KW)
Therefore, by solving the above calculation we get,

m = 40 microgram

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The power obtained in a reactor using U235 disintegration is 1000 kW . What is the mass decay of U235 per hour ?

As, E = mc2 1000 * 103 * 3600 = m (3 * 108)2 (we took 1000 × 103 since KW) Therefore, by solving the above calculation we get, m = 40 microgram

The power obtained in a reactor using U²³⁵ disintegration is 1000 kW . What is the mass decay of U²³⁵ per hour ?

As, E = mc²

1000 * 10³ * 3600 = m (3 * 10⁸)²
(we took 1000 × 10³since KW)
Therefore, by solving the above calculation we get,

m = 40 microgram