The power of $50$ kg man who climbs up height of $5$ min $10$ s is $[g = 10 m / s^{2}]$

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Solution

The power of $= 50 k g$ man who climbsup height of $5$ 10$ s
is $g = 10 m / s^{2}$
$P = \frac{m g}{t} = \frac{50 \times 10}{310} = \frac{50}{31} = 1.61 W$

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