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Cutting of Thin Lenses

The power of ...

Question

The power of a biconcave lens having a focal length of 25 cm is:

A

-4D

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B

-8D

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C

-0.25D

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D

None of the above

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Solution

The correct option is A -4D
Focal length $= 25 c m = \frac{1}{4} m$
So, for a biconcave lens power is $P = \frac{1}{f} D = - 4 D$

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