The power of a lens is + 2.0 D. Its focal length should be : (a) 100 cm (b) 50 cm (c) 25 cm (d) 40 cm

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Solution

$F = \frac{1}{P} = \frac{1}{2} = 50 m$

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The power of a lens is + 2.0 D. Its focal length should be : (a) 100 cm (b) 50 cm (c) 25 cm (d) 40 cm

F=1P=12=50 m

$F = \frac{1}{P} = \frac{1}{2} = 50 m$