The power of a lens is, - 2 D. What is its focal length ?

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Solution

The power of a lens is, - 2 D
so

$F = \frac{1}{P}$

$= \frac{1}{- 2} = - 0.5 m$

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The power of a lens is, - 2 D. What is its focal length ?

The power of a lens is, - 2 D so F=1P =1−2=−0.5 m

The power of a lens is, - 2 D
so

$F = \frac{1}{P}$

$= \frac{1}{- 2} = - 0.5 m$