The power of a pump takes 10 s to lift 100 kg of water tank situated at a height of 20 m is:

2 \times 10^{4}

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2 \times 10^{3}

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200 W

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1 kW

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Solution

The correct option is B $2 \times 10^{3}$ W
Here, work done $W =$ potential energy $= m g h = 100 \times 10 \times 20 = 20000 J$
The required power $P = W / t = 20000 / 10 = 2 \times 10^{3}$ W

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Similar questions

g = 10 m s^{- 2}

10 s

100 kg

20 m

What is the power of a pump which takes 10 seconds to lift 100 kg of water to a water tank situated at a height of 20 m? Take $g = 10 m s^{- 2}$

[T a k e g = 10 m / s^{2}]

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