The power of a pump, which can pump $200 k g$ water to a height of $200 m$ in $10 s$ is:(Take $g = 10 {m s}^{- 2}$ )

40 k W

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400 k W

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80 k W

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960 k W

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Solution

The correct option is D $40 k W$
Mass of water : $m = 200$ $k g$
Height upto which the water is raised : $h = 200$ $m$
Work done : $W = m g h = 200 \times 10 \times 200 = 400000$ $J$
Power of the pump : $P = \frac{W}{t} = \frac{400000}{10} = 40000$ $W = 40$ $k W$

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The power of a pump, which can pump 200kg of water to a height of 200m in 10sec is ( $g = 10 m / s^{- 2}$ )

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